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EddieУчастник
Ещё на мотив Эдди
№1. Белые начинают и выигрывают
А. Моисеев, ШР, 9-9-2005You surprise me by going back to this fine motive. But not only 20, 6, 1 is possible, the move 28 (43×32) 37 wins too, I’m afraid.
EddieУчастникБелые начинают и выигрывают
А. Моисеев, ШР, 9-9-2005Alex, this one is about the same as the next problem, made by D. van den Berg in 1999:
EddieУчастникFound this one:
08/09/16/28/32/37/40 — 19/21/24/29/47/49/50
S.M. van Eijk, made in 2003 , published in Spectrum (2004)
EddieУчастникYes — Kuiper was the second name ringing in my head
One thing — it does not say when it was created.
But I have been showing it since the 1970s, at least 30 years ago.Thanks Eddie for the research.
?? What do you mean ??? There was no research by me. As pointed out before I can only give information about 7×7 positions
EddieУчастник02/07/11/13/18/28/36 — 16/22/27/33/37/38/44
H. Laros (De Problemist, feb. 1985)06/09/12/19/27/33/35 — 16/22/31/41/42/45/48
C.M. Koene (DamEldorado, nov. 1974)EddieУчастникalemo wrote:Вопрос всем — какая редакция лучше и почему ?№1.
Problem is already made by A. Uwarov in 1998.
EddieУчастникMartin van Dijk
(31) 36 and:
A: (38) 27 (382) 38 (41) 31 (47) 42
B: (38) 27 (372) 43 (48) 25 (37) 42, 493
C: (41) 27, 36 (27) 43 (32) 31
EddieУчастникYou’re in a productive mood, Alex ! This one, ending in a 1×1 or 2×2 opposition, is all yours !
EddieУчастникEddi, your turn ! 😆
Белые начинают и выигрывают
А. Моисеев, ШР, 8-30-2005АЛЕМО
Still want to make a problemist of me ? I’m a man of playing games. You are one of the experts here !
And the archive is killing most of my free time in this period !
By the way: «your» last one is a problem already made by Juskevic (published in Mir Miniatur).EddieУчастникThe problem below that Alex composed (13/22/24/28/31/41/45 — 20/29/34/38/40/42/43) was made in 2004 by Sijbrand van Eijk, he sent it to the archive last january. But it’s even older: there is a version made by A.A. Polman (no date) in the archive, with 38 on 39. Probably this is not written down correctly by mr Groeneveld, because of the dual 30, 47 and mr. Polman in fact also made the correct version.
EddieУчастникEddie, жаль что на (34) можно и 31(40,43)49,26 или37х
You’re right, it means that it has not two perfect winning endings. But (33) is the main variant and that one is OK. I found this motiv in a problem of Hlasny, but don’t know if it was found by him.
EddieУчастникGood luck, I’m curious what you compose.
But I’m NOT the author !!EddieУчастникTwo endings combined in one motiv. Don’t know who’s the author, can’t remember that I’ve seen this before:
Not difficult of course, but it looks fine:
+ (33) 37 (38) 27 (44) 372 (50) 28, 27
+ (34) 37 (40) 35 (43) 49 (48) 361 (39) 43, 26, 37
EddieУчастникThe arranged version of M. Tsvetov is almost the same as this one, which was made by J. Scheijen on 22-11-1937 and published in his collected work, part 2.
But because of the dual 10, 4 it is better to put 37 on 36.EddieУчастникThe manoeuvre 2 (38) 31 is very nice. But maybe white has the extra possibility 28 and 1 or 2 to go for a win.
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